Class 10 Math Shortcuts: Board Exam Speed Guide (CBSE 2026)

Class 10 math shortcuts complete board exam guide
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Class 10 CBSE Math board exam is one of the most important examinations of a student's academic life — and one of the most manageable once you know which chapters carry the most marks and how to solve each type of question efficiently.

The CBSE Class 10 Maths paper carries 80 marks in written exam plus 20 marks for internal assessment. It contains MCQs (20 marks), Very Short Answers (10 marks), Short Answers (18 marks), Long Answers (20 marks), and Case Study questions (12–15 marks). With the right shortcuts and chapter-wise strategy, scoring 90+ is entirely achievable for any student who practices consistently.

This guide covers all 7 units of the CBSE Class 10 Maths syllabus with shortcuts, tricks, and worked examples for every major chapter — designed for both last-minute revision and structured preparation.

Part 1: Unit-Wise Marks Distribution

CBSE Class 10 Maths 2026 — Weightage

UnitMarksPriority
Algebra21🔴 Very High
Geometry15🔴 Very High
Trigonometry12🔴 High
Statistics & Probability11🔴 High
Mensuration10🟡 Medium
Coordinate Geometry6🟡 Medium
Number Systems5🟢 Low
Total80 

Key takeaway: Algebra alone carries 21 marks — the single biggest unit. Algebra + Geometry + Trigonometry together = 48 marks = 60% of the paper. Master these three units and 90+ is within reach.

Part 2: Number Systems — 5 Marks, Easy Pickup

Despite low weightage, Number Systems questions are usually direct and fast to solve. Never skip them — these are the easiest marks in the paper.

Key Shortcuts

HCF and LCM using Prime Factorization:

  • HCF = Product of lowest powers of common prime factors
  • LCM = Product of highest powers of all prime factors

Worked Example 1:
Find HCF and LCM of 72 and 120.

72 = 2³ × 3²
120 = 2³ × 3 × 5
HCF = 2³ × 3 = 24
LCM = 2³ × 3² × 5 = 360
Verify: HCF × LCM = 24 × 360 = 8640 = 72 × 120 ✅

Worked Example 2 — Irrational Proof:
Prove that √3 is irrational.

Assume √3 = p/q (lowest terms)
→ 3q² = p² → 3 divides p → p = 3k
→ 3q² = 9k² → q² = 3k² → 3 divides q
But p and q can't both be divisible by 3 — contradiction.
∴ √3 is irrational ✅

Key Formula:
For any two positive integers a and b:
HCF(a, b) × LCM(a, b) = a × b

Part 3: Algebra — 21 Marks (Biggest Unit)

Algebra has 4 chapters — Polynomials, Linear Equations, Quadratic Equations, and Arithmetic Progressions. Together they dominate the paper.

Chapter 1 — Polynomials

Key Shortcuts:

For a quadratic ax² + bx + c:

  • Sum of zeros (α + β) = −b/a
  • Product of zeros (α × β) = c/a

Worked Example 3:
If α and β are zeros of 2x² − 5x + 3, find α + β and αβ.

α + β = 5/2
αβ = 3/2

Worked Example 4:
Find a polynomial whose zeros are 3 and −4.

Sum = −1, Product = −12
Polynomial = x² − (sum)x + (product) = x² + x − 12

Division Algorithm check: Dividend = Divisor × Quotient + Remainder

Chapter 2 — Linear Equations

Three methods — when to use which:

MethodUse When
SubstitutionOne equation has simple variable
EliminationCoefficients are easily matchable
Cross MultiplicationBoth equations in standard form

Worked Example 5:
Solve: 2x + 3y = 11, 2x − 4y = −24

Subtract: 7y = 35 → y = 5
Substituting: 2x + 15 = 11 → x = −2

Graphical shortcut for nature of solutions:

LinesSolution
IntersectingUnique solution
ParallelNo solution
CoincidentInfinite solutions

Chapter 3 — Quadratic Equations

Discriminant D = b² − 4ac — the master key:

D > 0Two distinct real roots
D = 0Two equal real roots
D < 0No real roots

Worked Example 6 — Factorization:
Solve: x² − 7x + 12 = 0

Find two numbers whose sum = −7 and product = 12 → −3 and −4
x² − 3x − 4x + 12 = 0
x(x − 3) − 4(x − 3) = 0
(x − 3)(x − 4) = 0
x = 3 or x = 4

Worked Example 7 — Quadratic Formula:
Solve: 2x² + x − 4 = 0

D = 1 + 32 = 33
x = (−1 ± √33) / 4
x = (−1 + √33)/4 or (−1 − √33)/4

Chapter 4 — Arithmetic Progressions (AP)

Two Core Formulas:

aₙ = a + (n − 1)d

Sₙ = n/2 × [2a + (n − 1)d] = n/2 × (a + l)

Where: a = first term, d = common difference, n = number of terms, l = last term

Worked Example 8:
Find the 15th term of AP: 3, 7, 11, 15...

a = 3, d = 4
a₁₅ = 3 + 14 × 4 = 3 + 56 = 59

Worked Example 9:
Find sum of first 20 terms of AP: 5, 8, 11...

S₂₀ = 20/2 × [2(5) + 19(3)] = 10 × [10 + 57] = 10 × 67 = 670

Shortcut — Find n when last term is given:
Last term of AP 3, 7, 11... is 79. Find n.

79 = 3 + (n − 1)4
76 = (n − 1) × 4
n − 1 = 19 → n = 20

Part 4: Coordinate Geometry — 6 Marks

Three formulas cover 90% of Coordinate Geometry questions.

Three Master Formulas

Distance Formula:
d = √[(x₂ − x₁)² + (y₂ − y₁)²]

Section Formula (internal division):
P = [(mx₂ + nx₁)/(m + n), (my₂ + ny₁)/(m + n)]

Midpoint Formula (m = n = 1):
Midpoint = [(x₁ + x₂)/2, (y₁ + y₂)/2]

Area of Triangle:
Area = ½ × |x₁(y₂ − y₃) + x₂(y₃ − y₁) + x₃(y₁ − y₂)|

Collinearity check: If Area = 0, points are collinear.

Worked Example 10:
Find midpoint of segment joining (3, −4) and (−7, 8).

Midpoint = [(3 − 7)/2, (−4 + 8)/2] = (−2, 2)

Worked Example 11:
Find area of triangle with vertices (1, 2), (4, 6), (−3, 2).

= ½ × |1(6 − 2) + 4(2 − 2) + (−3)(2 − 6)|
= ½ × |4 + 0 + 12|
= ½ × 16 = 8 sq. units

Part 5: Geometry — 15 Marks

Geometry has two chapters — Triangles and Circles. Both require theorem knowledge plus proof-writing skills.

Chapter 1 — Triangles

Must-Know Theorems:

  1. Basic Proportionality Theorem (BPT): If a line is drawn parallel to one side of a triangle, it divides the other two sides in the same ratio.
  2. Pythagoras Theorem: In a right-angled triangle, AC² = AB² + BC²
  3. Converse of Pythagoras: If AC² = AB² + BC², then angle B = 90°

Similarity shortcuts:

CriterionCondition
AATwo angles equal
SASTwo sides proportional + included angle equal
SSSAll three sides proportional

Worked Example 12:
In triangle ABC, DE ∥ BC, AD = 3, DB = 5, AE = 4.5. Find EC.

By BPT: AD/DB = AE/EC
3/5 = 4.5/EC
EC = 4.5 × 5/3 = 7.5

Pythagoras Trick — Common Triples:
3-4-5, 5-12-13, 8-15-17, 7-24-25
Any multiple works: 6-8-10, 9-12-15, etc.

Chapter 2 — Circles

Tangent Properties:

  1. Tangent ⊥ radius at point of contact
  2. Tangents from external point are equal in length
  3. Angle in a semicircle = 90°

Worked Example 13:
Two tangents PA and PB from external point P touch circle at A and B. PA = 5 cm. Find PB.

By equal tangent property: PB = 5 cm

Worked Example 14:
A tangent at point A makes angle 40° with chord AB. Find the inscribed angle in alternate segment.

By Tangent-Chord angle theorem: Inscribed angle = 40°

Part 6: Trigonometry — 12 Marks

Trigonometry is pure formula application — once you know the identities and standard values, marks are guaranteed.

Trigonometric Values Table

Angle30°45°60°90°
sin01/21/√2√3/21
cos1√3/21/√21/20
tan01/√31√3

Memory trick for sin: √0, √1, √2, √3, √4 — all divided by 2 = 0, 1/2, 1/√2, √3/2, 1

Core Identities

sin²θ + cos²θ = 1

1 + tan²θ = sec²θ

1 + cot²θ = cosec²θ

Worked Example 15:
Prove: (sinθ + cosθ)² + (sinθ − cosθ)² = 2

LHS = sin²θ + 2sinθcosθ + cos²θ + sin²θ − 2sinθcosθ + cos²θ
= 1 + 1 = 2 = RHS

Worked Example 16 — Heights and Distances:
A tower 30 m high casts a shadow 30√3 m. Find angle of elevation.

tanθ = 30 / 30√3 = 1/√3
θ = 30°

Height and Distance Formulas

  • Angle of elevation: Object above horizontal → tanθ = height/distance
  • Angle of depression: Object below horizontal → same tanθ applies (alternate angles)

Part 7: Mensuration — 10 Marks

Mensuration questions always involve combinations of 3D shapes — frustum, sphere + cylinder, cone + hemisphere, etc.

Complete Formula Reference

ShapeCSATSAVolume
Cylinder2πrh2πr(r+h)πr²h
Coneπrlπr(r+l)⅓πr²h
Sphere4πr²4πr²4/3 πr³
Hemisphere2πr²3πr²2/3 πr³
Frustumπ(r₁+r₂)lπh/3 × (r₁² + r₂² + r₁r₂)

Slant height l = √(h² + r²)

Worked Example 17:
A solid is made of a cylinder (r = 5 cm, h = 10 cm) with hemisphere on top (r = 5 cm). Find volume.

Volume = πr²h + (2/3)πr³
= π × 25 × 10 + (2/3) × π × 125
= 250π + 250π/3
= π × (750 + 250)/3
= 1000π/3 ≈ 1047 cm³

Part 8: Statistics and Probability — 11 Marks

Statistics — Three Measures

Mean (Direct Method):
x̄ = Σfᵢxᵢ / Σfᵢ

Assumed Mean Method (when values are large):
x̄ = a + (Σfᵢdᵢ / Σfᵢ) — where dᵢ = xᵢ − a

Median:
Median = l + [(n/2 − cf) / f] × h

Mode:
Mode = l + [(f₁ − f₀) / (2f₁ − f₀ − f₂)] × h

Worked Example 18 — Median:
Class 20–30: l = 20, f = 25, cf = 20, h = 10, n = 50

Median = 20 + [(25 − 20)/25] × 10 = 20 + 2 = 22

Probability — Clean and Fast

P(E) = Favourable outcomes / Total outcomes

Key rules:

  • P(E) + P(not E) = 1
  • 0 ≤ P(E) ≤ 1
  • P(certain event) = 1, P(impossible event) = 0

Worked Example 19:
A card is drawn from a deck of 52. Probability of face card?

Face cards = 12 (J, Q, K × 4 suits)
P = 12/52 = 3/13

Part 9: Answer-Writing Speed Strategy

Question-Wise Time Allocation

SectionQuestionsMarksTime
MCQs (Sec A)181820 min
Assertion-Reason223 min
VSA (2 marks)51015 min
SA (3 marks)61825 min
LA (5 marks)42030 min
Case Study312–1520 min
Total3880113 min

Board exams give 180 minutes for 80 marks — 67 minutes buffer for revision. Use it.

Board Exam Answer Tips

  1. Show all steps — partial marks awarded for method even if final answer is wrong
  2. Box your final answer — examiners spot it immediately
  3. Write formulas first then substitute — gets method marks
  4. Draw diagrams for Geometry and Trigonometry — always speeds up understanding
  5. Attempt MCQs first — they are confidence builders and time efficient
  6. Internal choice — always read both options before solving

30-Day Revision Plan

DaysFocusDaily Time
1–5Algebra — Polynomials + Linear Equations60 min
6–10Algebra — Quadratic + AP60 min
11–14Geometry — Triangles + Circles50 min
15–18Trigonometry + Heights & Distances50 min
19–21Statistics + Probability40 min
22–23Coordinate Geometry + Number Systems30 min
24–25Mensuration40 min
26–28Previous Year Papers (full paper timed)180 min
29–30Weak chapter revision + Formula revision60 min

Frequently Asked Questions

Algebra is the single most important unit with 21 marks. Within Algebra, Quadratic Equations and Arithmetic Progressions together typically contribute 10–14 marks and appear in every question type — MCQ, short answer, long answer, and case study. No other chapter appears in as many sections.

MCQs carry 20 marks in total (18 MCQs + 2 Assertion-Reason). For MCQs, elimination and back-substitution are the fastest solving methods — plug the answer options back into the question rather than solving from scratch. This saves 30–40 seconds per question.

Case study questions carry 4–5 marks and are scenario-based. Read the full paragraph first, identify the mathematical concept being tested (usually Mensuration, Statistics, or Coordinate Geometry), then solve each sub-question independently. Sub-parts are usually progressive — part (i) often gives a value needed for part (ii).

Probability is among the most straightforward scoring topics in Class 10 Maths. Questions follow standard formats — cards, dice, coins, coloured balls — with direct formula application. Solving 20–25 NCERT and previous year Probability questions guarantees full marks in this chapter.

Class 10 board exam Maths rewards accurate calculation more than raw speed — but fast arithmetic still saves critical minutes that can be used for checking. SpeedMath.in's calculation drills build the mental arithmetic reflexes needed for MCQ solving, value substitution in formulas, and quick verification. Students who practice regular arithmetic drills make fewer carrying errors in multi-step SA and LA questions — exactly where partial marking saves or costs marks.

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