Quadratic Equation Solver

Enter coefficients for ax² + bx + c = 0

Please enter valid numbers. Note: 'a' cannot be 0.

Enter two roots α and β to form the quadratic equation x² − (α+β)x + αβ = 0

Please enter valid numbers for both roots.

Enter a, b, c to check the nature of roots without solving

Please enter valid numbers. Note: 'a' cannot be 0.

How to Use

1
Enter Coefficients

Type the values of a, b, and c for your equation ax² + bx + c = 0. 'a' must not be zero.

2
Choose Mode

Use "Solve Equation" for roots, "Form from Roots" to build an equation, or "Nature of Roots" to check the discriminant.

3
Get Full Solution

Click Calculate to see the roots, discriminant, Vieta's formulas, and complete step-by-step working.

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Frequently Asked Questions

The quadratic formula is x = (−b ± √(b² − 4ac)) / 2a. It solves any quadratic equation ax² + bx + c = 0 where a ≠ 0. The ± sign gives two roots.

The discriminant is D = b² − 4ac. If D > 0: two distinct real roots. If D = 0: one repeated real root. If D < 0: two complex conjugate roots (no real solution). D is the key to predicting root type without solving.

For ax² + bx + c = 0 with roots α and β: Sum α + β = −b/a and Product αβ = c/a. These are Vieta's formulas. In SSC and bank exams, questions often ask you to find these without computing individual roots.

If α and β are the roots, the equation is x² − (α + β)x + αβ = 0. Simply compute the sum and product of the given roots and substitute. Use the "Form from Roots" tab above.

When D = b² − 4ac < 0, the equation has no real roots. The roots become complex conjugates: x = −b/2a ± i√|D|/2a. Complex roots always occur in pairs and are equal in magnitude.

Yes. A quadratic equation must have x² as its highest power and the coefficient 'a' must be non-zero. If a = 0, it becomes a linear equation (bx + c = 0), not quadratic.