Arithmetic Progression Calculator

Enter the first term (a), common difference (d), and term number (n) to find aₙ and Sₙ.

Please enter valid numbers. n must be a positive integer.

Given a term value, find which position it occupies in the AP.

Please enter valid numbers. d cannot be 0 (use Simple Probability tab instead).

Given the first term, last term, and number of terms, find d and the sum Sₙ.

Please enter valid numbers. n must be an integer ≥ 2.

How to Use

1
Choose a Mode

Pick nth Term & Sum for standard AP questions, Find Term Number to find which term equals a value, or Find Common Difference when first and last terms are known.

2
Enter the Known Values

Fill in the first term (a), common difference (d), and term number (n) — or whichever three values your problem gives you.

3
Read the Solution

Get the nth term (aₙ), sum (Sₙ), and a complete step-by-step breakdown with the AP series listed.

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Frequently Asked Questions

aₙ = a + (n − 1) × d, where a is the first term, d is the common difference, and n is the term position. Example: AP 3, 7, 11, 15… → a = 3, d = 4, so the 10th term = 3 + 9 × 4 = 39.

Sₙ = n/2 × (2a + (n − 1)d). Equivalently, Sₙ = n/2 × (first term + last term). Example: sum of first 10 terms of 3, 7, 11… → S₁₀ = 10/2 × (6 + 36) = 5 × 42 = 210.

d = (last term − first term) / (n − 1). Example: AP 5, 8, 11, 14 has 4 terms → d = (14 − 5) / (4 − 1) = 9/3 = 3. You can verify: each consecutive pair differs by 3.

Set aₙ = t and solve: n = (t − a)/d + 1. If the result is a positive integer, t belongs to the AP at position n. If not a positive integer, t is not a term of the AP. Example: is 39 a term of 3, 7, 11…? n = (39 − 3)/4 + 1 = 36/4 + 1 = 10. Yes, 39 is the 10th term.

In an AP, terms differ by a constant (common difference d): 2, 5, 8, 11 (d = 3). In a GP, terms multiply by a constant (common ratio r): 2, 6, 18, 54 (r = 3). The AP sum formula is Sₙ = n/2 × (2a + (n−1)d); the GP sum formula is Sₙ = a(rⁿ − 1)/(r − 1).